在listview中获取JSON响应以及如何在listview中显示它？-GetJSONresponseinlistviewandhowtoshowitinlistview?

I am a beginner in Android. I want to get a JSON response in a list and show it in a ListView . How to do this?
Here is my code for JSON post.

我是Android的初学者。我想在列表中获取JSON响应并在ListView中显示它。这个怎么做？这是我的JSON帖子的代码。

public class NewTest extends AppCompatActivity {    TextView
txtJson;
       Button btnOkay;
        @Override
       protected void onCreate(Bundle savedInstanceState) {
           super.onCreate(savedInstanceState);
           setContentView(R.layout.activity_new_test);
            txtJson= (TextView) findViewById(R.id.txtJson);

           assert (findViewById(R.id.btnOkay)) != null;
           (findViewById(R.id.btnOkay)).setOnClickListener(new View.OnClickListener() {
               @Override
               public void onClick(View v) {   new TaskPostWebService("written url here").execute(((TextView)   
findViewById(R.id.txtJson)).getText().toString());

               }
           });  }
       private class TaskPostWebService extends AsyncTask {
           private String url;
           private ProgressDialog progressDialog;
           private JSONParser jsonParser;

           public TaskPostWebService(String url ){

               this.url = url;
           }
           @Override
           protected void onPreExecute() {
               super.onPreExecute();
               progressDialog = ProgressDialog.show(NewTest.this,"","");
           }

           @Override
           protected String doInBackground(String... params) {

            String fact = "";
               try {

                   final MediaType JSON = MediaType.parse("application/json");

                   android.util.Log.e("charset", "charset - " + JSON.charset());
                   OkHttpClient client = new OkHttpClient();
       //Create a JSONObject with the data to be sent to the server
                   final JSONObject dataToSend = new JSONObject()
                           .put("nonce", "G9Ivek")
                           .put("iUserId", "477");

                   android.util.Log.e("data - ", "data - " + dataToSend.toString());
       //Create request object
                   Request request = new Request.Builder()
                           .url("written url here")
                           .post(RequestBody.create(JSON, dataToSend.toString().getBytes(Charset.forName("UTF-8"))))
                           .addHeader("Content-Type", "application/json")
                           .build();

                   android.util.Log.e("request - ", "request - " + request.toString());
                   android.util.Log.e("headers - ", "headers - " + request.headers().toString());
                   android.util.Log.e("body - ", "body - " + request.body().toString());
       //Make the request
                   Response respOnse= client.newCall(request).execute();
                   android.util.Log.e("response", " " + response.body().string()); //Convert the response to String
                   String respOnseData= response.body().string();
       //Construct JSONObject of the response string
                   JSONObject dataReceived = new JSONObject(responseData);
       //See the response from the server
                   Log.i("response data", dataReceived.toString());
               }
               catch (Exception e){
                   e.printStackTrace();
               }
               return fact;
           }

           @Override
           protected void onPostExecute(String s) {
               super.onPostExecute(s);
               TextView text = (TextView) findViewById(R.id.txtJson);
               text.setText(s); 
               progressDialog.dismiss();
           }
       }

So, how can I get a response in a list and show it in a ListView?

那么，我如何在列表中获得响应并在ListView中显示它？

2 个解决方案

ArrayList arrayListJson;
ArrayList arrayList;
ArrayAdapter adapter;
ListView listView = (ListView) fragmentView.findViewById(R.id.listView);
adapter = new ArrayAdapter<> (getActivity(), android.R.layout.simple_list_item_1, arrayList);
listView.setAdapter(adapter);

JSONObject jRespOnse= new JSONObject(responseStr);
JSONArray jArray= jResponse.getJSONArray("OUTER_KEY");
for (int i = 0; i