如何从命令行中找到Set-Subset的两个文件？-HowtofindtheSet-Subsetoftwofilesfromthecommandline?

13  

This will suppress common lines:

这将抑制常见的行:

comm -3 a b

5  

How about this:

这个怎么样:

grep -v -f B A > C

3  

You can do this with diff as well. Diff (unlike @johlo's grep answer) cares about order, works on non-sorted files (unlike @johnshen64's comm answer) :

您也可以使用差异来完成此操作。 Diff(不像@ johlo的grep答案)关心顺序,适用于非排序文件(不像@ johnshen64的comm回答):

$ cat a
a
b
c
d
e
$ cat b
a
b
f
d
e
$ diff -dbU0 a b
--- a   2012-05-18 16:02:30.603386016 -0400
+++ b   2012-05-18 16:02:45.547817122 -0400
@@ -3 +3 @@
-c
+f

So you can use a pipeline to get just the omitted lines—considering order:

因此,您可以使用管道来获取省略的行 - 考虑顺序:

$ diff -dbU0 a b | tail -n +4 | grep ^- | cut -c2-
c

1  

This join command will do what you're asking:

这个join命令可以满足您的要求:

join -v 1 fileA fileB > fileC

Demonstration:

$ cat fileA
a
c
d
g
h
t
u
v
z
$ cat fileB
a
d
g
t
u
z
$ join -v 1 fileA fileB
c
h
v

This assumes sorted files as you stated in your question. For unsorted files:

这假定您在问题中声明的已排序文件。对于未分类的文件:

join -v 1 <(sort fileA) <(sort fileB)

0  

Awk Solution

Input files

a

aaa
bbb
ccc

b

ccc
ddd
eel

Code

awk ' NR==FNR { A[$0]=1; next; }
{ if ($0 in A) { A[$0]=0; } }
END { for (k in A) { if (A[k]==1) { print k; } } } ' a b > c

c (Output file)

c(输出文件)

bbb
aaa