Here's my rake routes:

这是我的耙路线:

  Prefix Verb   URI Pattern                    Controller#Action
     root GET    /                              cards#index
    cards GET    /cards(.:format)               cards#index
         POST    /cards(.:format)               cards#create
 new_card GET    /cards/new(.:format)           cards#new
edit_card GET    /cards/:id/edit(.:format)      cards#edit
     card GET    /cards/:id(.:format)           cards#show
        PATCH    /cards/:id(.:format)           cards#update
          PUT    /cards/:id(.:format)           cards#update
       DELETE    /cards/:id(.:format)           cards#destroy
          GET    /cards/:id(.:format)           cards#show
`

..... So, because of the above, the code below is of course not doing what i want it to do, but here's my view page as of now:

.....因此，由于上面的原因，下面的代码当然没有做我想做的事情，但是这是我现在的视图页面:

  

  




    
 
 <%= button_tag(type: 'button') do %>

    
 <%= @card.word_text %>    

    
<%= link_to 'Tap to flip card', card_path(@card) %>
  
    
 <%= content_tag(:strong,'Tap to flip the card') %> 

    <% end %>




 
 <%= button_tag(type: 'button') do %>

    
<%= link_to 'New Card', cards_path(@next) %>
  

    
 <%= content_tag(:strong,'New Card') %> 

<% end %>

To be honest, I am very stuck on how to create a path from my index page (which is displaying card #1, or @card) BACK to a new index page where card #2, or @next, is displayed instead... any help would be much appreciated!

老实说，我非常纠结于如何创建一个路径，从我的索引页(显示的是card #1或@card)返回到一个新的索引页，其中显示的是card #2或@next……如有任何帮助，我们将不胜感激!

1 个解决方案

@card = Card.find(params[:id])
@next = Card.where('id > ?', @card.id).first
@next = Card.first if @next.nil?

def next  # This is a method on an INSTANCE of Card, not the Class
  next_card = Card.where('id > ?', self.id).first
  next_card = Card.first if next_card.blank?
  next_card
end

<%= link_to 'New Card', card_path(@card.next) %>