// E
#include
using namespace std;
#pragma comment(linker, "/STACK:102400000,102400000")
#define rep(i,a,b) for (int i=a; i<=b; ++i)
#define per(i,b,a) for (int i=b; i>=a; --i)
#define mes(a,b) memset(a,b,sizeof(a))
#define INF 0x3f3f3f3f
#define MP make_pair
#define PB push_back
#define fi first
#define se second
typedef long long ll;
const int N = 100005;
struct Point { double x, y; };
struct Point point[N], *px[N], *py[N];
double get_dis(Point *p1,Point *p2) {
return sqrt((p1->x-p2->x)*(p1->x-p2->x)+(p1->y-p2->y)*(p1->y-p2->y));
}
bool cmpx(Point *p1,Point *p2) { return p1->xx; }
bool cmpy(Point *p1,Point *p2) { return p1->yy; }
double min(double a,double b) { return aa:b; }
double closest(int s,int e)
{
if(s+1==e)
return get_dis(px[s],px[e]);
if(s+2==e)
return min(get_dis(px[s],px[s+1]),min(get_dis(px[s+1],px[e]),get_dis(px[s],px[e])));
int mid=(s+e)>>1;
double ans=min(closest(s,mid),closest(mid+1,e));//递归求解
int i, j, cnt=0;
for(i=s; i<=e; i++)//把x坐标在px[mid].x-ans~px[mid].x+ans范围内的点取出来
{
if(px[i]->x>=px[mid]->x-ans && px[i]->x<=px[mid]->x+ans)
py[cnt++]=px[i];
}
sort(py, py+cnt, cmpy);//按y坐标排序
for(i=0; i)
{
for(j=i+1;j//py数组中的点是按照y坐标升序的
{
if(py[j]->y-py[i]->y>=ans) break;
ans=min(ans,get_dis(py[i],py[j]));
}
}
return ans;
}
/*void Init()
{
for(int i=1; i<=n; ++i) {
scanf("%lf%lf", &point[i].x, &point[i].y);
px[i] = &point[i];
}
sort(px+1, px+1+n);
}*/
int n;
double ai, sum[N];
int main()
{
scanf("%d", &n);
rep(i,1,n)
{
scanf("%lf", &ai);
sum[i]=sum[i-1]+ai;
point[i].x=1.0*i, point[i].y=sum[i];
px[i] = &point[i];
}
sort(px+1, px+1+n, cmpx);
double ans = closest(1, n);
printf("%.0f\n", ans*ans);
return 0;
}