C#学习教程：从多个数组生成所有可能的组合（C＃/VB.NET）分享

根据Eric Lippert撰写的文章

void Main() { var set1 = new object[]{'a', 'b', 'c'}; var set2 = new object[]{1,2,}; var set3 = new object[]{'x', 'y', 'z'}; string.Join(", ", new[] {set1, set2, set3}.CartesianProduct().Select(item => item.ToArray()).Select(item => string.Format("({0},{1},{2})", item[0], item[1], item[2]))).Dump(); } public static class CartesianProductContainer { public static IEnumerable> CartesianProduct(this IEnumerable> sequences) { IEnumerable> emptyProduct = new[] { Enumerable.Empty() }; return sequences.Aggregate( emptyProduct, (accumulator, sequence) => from accseq in accumulator from item in sequence select accseq.Concat(new[] {item})); } } 

输出：

 (a,1,x), (a,1,y), (a,1,z), (a,2,x), (a,2,y), (a,2,z), (b,1,x), (b,1,y), (b,1,z), (b,2,x), (b,2,y), (b,2,z), (c,1,x), (c,1,y), (c,1,z), (c,2,x), (c,2,y), (c,2,z) 

第一种方法

您可以使用嵌套For循环

 for (int i=0; i