作者:god | 来源:互联网 | 2024-10-30 17:03
题目:
Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1
/ \
2 3
\
5
All root-to-leaf paths are:
["1->2->5", "1->3"]
求一个二叉树的所有路径
代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;(
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void RootPath(vector<string>& resultVec, TreeNode *root, string s)
{
if (root->left == NULL && root->right == NULL)
{
resultVec.push_back(s);
return;
}
if (root->left)
{
RootPath(resultVec, root->left, s + "->" + to_string(root->left->val));
}
if (root->right)
{
RootPath(resultVec, root->right, s + "->" + to_string(root->right->val));
}
}
vector<string> binaryTreePaths(TreeNode* root) {
vector<string> result;
if (root == NULL) return result;
RootPath(result, root, to_string(root->val));
return result;
}
};