useQuery的奇怪问题：未读取查询参数

我有一个将字符串（userToFetch）作为变量传递给参数化查询的组件。该组件如下所示：

// pages/index.jsx

import React from 'react';
import { useQuery } from '@apollo/react-hooks';
import gql from 'graphql-tag';

const GET_USERS = gql`
  query users ($limit: Int!, $username: String!) {
    users (limit: $limit, where: { username: $username }) {
      username
      firstName
    }
  }
`;

const Home = () => {
  const userToFetch = 'jonsnow';

  const {
    loading,
    error,
    data,
  } = useQuery(
    GET_USERS,
    {
      variables: { limit: 2, username: userToFetch },
      notifyOnNetworkStatusChange: true,
    },
  );

  if (loading) {
    return 
Loading...
;
  }

  if (error) {
    return 
Error: {JSON.stringify(error)}
;
  }
  return (
    

      

        {data.users.map(user => {
          return 
{user.username} {user.firstName}
;
        })}
      
    
  );
};

export default Home;

这就是我配置Apollo客户端的方式：

// /apollo-client.js

import { ApolloClient } from 'apollo-client';
import { InMemoryCache } from 'apollo-cache-inmemory';
import withApollo from 'next-with-apollo';
import { createHttpLink } from 'apollo-link-http';
import fetch from 'isomorphic-unfetch';

const GRAPHQL_URL = 'https://dev.schandillia.com/graphql';

const link = createHttpLink({
  fetch, // Switches between unfetch & node-fetch for client & server.
  uri: GRAPHQL_URL
});

// Export a HOC from next-with-apollo
// Docs: https://www.npmjs.com/package/next-with-apollo
export default withApollo(
  // You can get headers and ctx (context) from the callback params
  // e.g. ({ headers, ctx, initialState })
  ({ initialState, ctx }) => {
    console.log('initialState', initialState);
    console.log('ctx', ctx);

    return new ApolloClient({
      link: link,
      cache: new InMemoryCache()
        //  rehydrate the cache using the initial data passed from the server:
        .restore(initialState || {})
    })
  }
);

该数据库是以下各项的集合users：

"users": [
      {
        "username": "negger",
        "firstName": "Arnold",
        "lastName": "Schwarzenegger"
      },
      {
        "username": "jonsnow",
        "firstName": "Jon",
        "lastName": "Snow"
      },
      {
        "username": "tonystark",
        "firstName": "Tony",
        "lastName": "Stark"
      }
    ]
  }

现在，尽管这应该工作（当我在位于https://dev.schandillia.com/graphql的 graphql游乐场中运行查询时，它确实可以工作），但代码运行时就好像该where子句不存在一样！它只是返回所有结果，就像正在运行的查询是：

users {
  _id
  username
  firstName
}

为了重现该问题，请访问https://www.schandillia.com。该页面应该显示仅包含一个由匹配的username-firstName值组成的元素的列表：jonsnow Jon但是它返回两个条目，negger Arnold和jonsnow Jon（指定limit但完全忽略where）。现在，使用https://dev.schandillia.com/graphql中jonsnow的where参数运行相同的查询：

{
  users(where: { username: "jonsnow" }) {
    _id
    username
    firstName
  }
}

结果将完全符合预期：

{
  "data": {
    "users": [
      {
        "_id": "5d9f261678a32159e61018fc",
        "username": "jonsnow",
        "firstName": "Jon",
      }
    ]
  }
}

我在俯视什么？

PS：该仓库已在https://github.com/amitschandillia/proost/tree/master/apollo-nextjs上提供了参考。

更新：为了跟踪根本原因，我尝试在中记录一些值apollo-client.js：

console.log('initialState', initialState);

奇怪的是，输出显示正确的查询以及要传递的变量，但结果错误：

...
ROOT_QUERY.users({"limit":2,"where":{"username":"jonsnow"}}).0:
  firstName: "Arnold"
  username: "negger"
  __typename: "UsersPermissionsUser"
...

更新：这是我的Apollo客户端开发人员工具中结果的屏幕截图：