Oracle查询语句面试题

01． 查询员工表所有数据，并说明使用*的缺点 select * from emp; 01．查询职（job）为

01． 查询员工表所有数据，并说明使用*的缺点

select * from emp;

01．查询职（job）为'PRESIDENT'的员工的工资

select sal from emp where job='PRESIDENT';

02．查询佣金为0或为null的员工的信息

select * from emp where comm is null or comm=1;

03．查询入职日期在1981-5-1到1981-12-31之间的所有员工的信息

select * from emp where hiredate between to_date(‘1-5月-81’) and to_date(‘31-12月-81’)

04．.查询所有名字长度为4的员工的员工的编号，姓名

select empno,ename from emp where length(ename)=4

05．显示10号部门饿所有经理和20号部门的所有员工

select * from emp where job='MANAGER' and deptno=10 or job='CLERK' and deptno=20;

06．显示姓名没有'L'字的员工的详细信息或含有'SM'字的员工信息

select * from emp where ename not like '%L%' or ename like '%SM%';

07．显示各个部门经理的工资

select deptno,sal from emp where job='MANAGER';

08．显示佣金收入比工资高的员工的详细信息

select * from emp where comm>sal;

10．把hiredate列看做是员工的生日，求本月过生日的员工：

SQL> select * from emp

where to_char(hiredate,'mm')=to_char(sysdate,'mm');

11．把hiredate列看做是员工的生日，求下月过生日的员工

SQL> select * from emp

where to_char(hiredate,'mm')=to_char(add_months(sysdate,1

),'mm');

12.求1982年入职的员工

SQL> select * from emp where to_char(hiredate,'yyyy')='1982';

hiredate是date类型的，1982是字符串类型的，类型匹配才可以

13．求1981年下半年入职的员工

select * from emp

where hiredate between to_date('1981-7-1','yyyy-mm-dd')

and to_date('1982-1-1','yyyy-mm-dd')-1;

注：to_char()函数和to_date()函数

to_char()函数是把日期的类型转换为指定的格式

to_date()是把字符串转换为日期类型

-1的原因是更精确

14．求1981年各个月入职的员工个数

SQL> select to_char(hiredate,'mm'),count(*) from emp where to_char(hiredate,'yyy

y')='1981' group by to_char(hiredate,'mm') order by to_char(hiredate,'mm');

或

select to_char(hiredate,'mm'),count(*) from emp where to_char(hiredate,'yyyy')='1981' group by to_char(hiredate,'mm') order by to_char(hiredate,'mm');

PartII

01 .查询各个部门的平均工资

SQL> select deptno,avg(nvl(sal,0)) from emp group by deptno;

02.显示各种职位的最低工资

SQL> select job,min(sal) from emp group by job;

03．按照入职日期由新到旧排列员工信息

SQL> select hiredate from emp order by hiredate desc;

04．查询员工的基本信息，附加其上级的姓名（自关联）

SQL> select e.*,e1.ename from emp e,emp e1 where e.mgr=e1.empno;

05．显示工资比’ALLEN’高的所有员工的姓名和工作

SQL> select ename,sal from emp where sal>(

select sal from emp where ename='ALLEN');

06．显示与scott从事相同工作的员工的信息（子查询）

SQL> select * from emp where job=(

select job from emp where ename='SCOTT');

07．显示销售部(‘SALES’)员工的姓名

SQL> select e.ename from emp e inner join dept d on e.deptno=d.deptno where d.dname='SALES';

08．显示与30号门’MARTIN’员工工资相同的员工的姓名和工资

SQL> select ename,sal from emp where sal=(select sal from emp where deptno=30 and ename='MARTIN');

09．查询所有工资高于平均工资（包括所有员工）的销售人员

SQL> select * from emp where sal>(

select avg(sal) from emp) and job='SALESMAN';

或

SQL> select * from emp where job='SALESMAN' and sal>(

select avg(sal) from emp);

10．显示所有职员的姓名及其所在部门的名称和工资(表连接)

SQL> select e.*,e.sal,d.dname from emp e inner join dept d on e.deptno=d.deptno;

11．查询在研发部(RESEARCH)工作人员的编号，姓名，，工作部门，工作所在地

SQL> select e.empno,e.ename,d.dname,d.loc from emp e inner join dept d on e.deptno=d.deptno where dname='RESEARCH';

12．查询各个部门的名称和员工人数

select e.deptno,d.dname,count(*) from emp e inner join dept d on e.deptno=d.deptno group by e.deptno,d.dname

分析：

SQL> select d.dname from emp e inner join dept d on e.deptno=d.deptno group by e.deptno,d.dname;

DNAME

--------------

ACCOUNTING

RESEARCH

SALES

SQL> select e.deptno,d.dname from emp e inner join dept d on e.deptno=d.deptno group by e.deptno,d.dname;

DEPTNO DNAME

------ --------------

10 ACCOUNTING

20 RESEARCH

30 SALES

SQL> select e.deptno,d.dname,count(*) from emp e inner join dept d on e.deptno=d.deptno group by e.deptno,d.dname;

DEPTNO DNAME COUNT(*)

------ -------------- ----------

10 ACCOUNTING 3

20 RESEARCH 5

30 SALES 6

13．查询各个部门员工工资大于平均工资（平均工资包括所有员工）的人数和员工职位(子查询)

SQL> select count(*),job from emp where sal>(select avg(sal) from emp) group by job;

14．查询工资相同的员工的工资和姓名（子查询）

SQL> select sal,ename from emp e where(select count(*) from emp where sal=e.sal group by sal)>1;

或

SQL> select e.sal,e.ename from emp e,emp e1 where e.sal=e1.sal and e.ename<>e1.ename;