pythonprint时清除上一行_如何在python中覆盖以前的打印到stdout？

一个更清洁&＃xff0c;更“即插即用”的版本&＃64; Nagasaki45的回答&＃xff1a;

def print_statusline(msg: str):

last_msg_length &＃61; len(print_statusline.last_msg) if hasattr(print_statusline, &＃39;last_msg&＃39;) else 0

print(&＃39; &＃39; * last_msg_length, end&＃61;&＃39;\r&＃39;)

print(msg, end&＃61;&＃39;\r&＃39;)

sys.stdout.flush() # Some say they needed this, I didn&＃39;t.

print_statusline.last_msg &＃61; msg

# Then simply use like this:

for msg in ["Initializing...", "Initialization successful!"]:

print_statusline(msg)

time.sleep(1)

# If you want to check that the line gets cleared properly:

for i in range(9, 0, -1):

print_statusline("{}".format(i) * i)

time.sleep(0.5)与其他许多答案不同&＃xff0c;它可以使用不同长度的字符串正常工作&＃xff0c;因为它会清空带有空格的行。也适用于Windows。