Python中实现Base64解码：将Base64编码的数据转换为数组形式

我使用这个方便的Javascript函数来解码base64字符串并得到一个数组作为返回。在

这是字符串&＃xff1a;base64_decode_array(&＃39;6gAAAOsAAADsAAAACAEAAAkBAAAKAQAAJgEAACcBAAAoAQAA&＃39;)

返回的内容如下&＃xff1a;

^{pr2}$

问题是我不太了解Javascript函数&＃xff1a;var base64chars &＃61; &＃39;ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789&＃43;/&＃39;.split("");

var base64inv &＃61; {};

for (var i &＃61; 0; i

base64inv[base64chars[i]] &＃61; i;

}

function base64_decode_array (s)

{

// remove/ignore any characters not in the base64 characters list

// or the pad character -- particularly newlines

s &＃61; s.replace(new RegExp(&＃39;[^&＃39;&＃43;base64chars.join("")&＃43;&＃39;&＃61;]&＃39;, &＃39;g&＃39;), "");

// replace any incoming padding with a zero pad (the &＃39;A&＃39; character is zero)

var p &＃61; (s.charAt(s.length-1) &＃61;&＃61; &＃39;&＃61;&＃39; ?

(s.charAt(s.length-2) &＃61;&＃61; &＃39;&＃61;&＃39; ? &＃39;AA&＃39; : &＃39;A&＃39;) : "");

var r &＃61; [];

s &＃61; s.substr(0, s.length - p.length) &＃43; p;

// increment over the length of this encrypted string, four characters at a time

for (var c &＃61; 0; c

// each of these four characters represents a 6-bit index in the base64 characters list

// which, when concatenated, will give the 24-bit number for the original 3 characters

var n &＃61; (base64inv[s.charAt(c)] <<18) &＃43; (base64inv[s.charAt(c&＃43;1)] <<12) &＃43;

(base64inv[s.charAt(c&＃43;2)] <<6) &＃43; base64inv[s.charAt(c&＃43;3)];

// split the 24-bit number into the original three 8-bit (ASCII) characters

r.push((n >>> 16) & 255);

r.push((n >>> 8) & 255);

r.push(n & 255);

}

// remove any zero pad that was added to make this a multiple of 24 bits

return r;

}

这些“<&＃xff1b;<&＃xff1b;”和“>&＃xff1b;>&＃xff1b;”字符的功能是什么。

或者Python有这样的函数吗&＃xff1f;在