python创建列表的方法解决问题,Python家庭作业创建新列表

分配&＃xff1a;

Write a function called splitList(myList, option) that takes, as input, a list and an option, which is either 0 or 1. If the value of the option is 0, the function returns a list consisting of the elements in myList that are negative, and if the value of the option is 1, the function returns a list consisting of the elements in myList that are even.

我知道如何确定数字是否为偶数以及数字是否为负数.我正在努力如何基于“选项”返回新的负数或偶数列表

到目前为止,这是我得到的&＃xff1a;

def splitList(myList):

newlist &＃61; []

for i in range(len(myList)):

if (myList[i]%2 &＃61;&＃61; 0):

newlist.append(myList [i])

return newlist

该程序出现以下错误&＃xff1a;

Traceback (most recent call last): File "", line 1, in

builtins.TypeError: splitList() takes exactly 1 positional argument (4 given)

解决方法:

正如我在评论中提到的那样,您应该对缩进进行标准化&＃xff1a;四个空格是Python标准.通常,您可以将编辑器设置为插入四个空格而不是制表符(也不希望将制表符与空格混合使用).

关于您的实际问题&＃xff1a;请尝试编写总共三个函数&＃xff1a;一个返回所有负值,一个返回偶数,另一个基于选项调用适当的函数.

def splitlist(myList, option):

if option &＃61;&＃61; 1:

return get_even_elements(myList)

elif option &＃61;&＃61; 0:

return get_negative_elements(myList)

def get_even_elements(myList):

pass # Implementation this method here.

def get_negative_elements(myList):

pass # Implementation this method here.

# Test it out!

alist &＃61; [-1, 2, -8, 5]

print splitlist(alist, 0)

print splitlist(alist, 1)

标签&＃xff1a;python,list

来源&＃xff1a; https://codeday.me/bug/20191011/1895150.html