详解python用模块zlib压缩与解压字符串和文件的方法代码

import zlib
message = &＃39;abcd1234&＃39;
compressed = zlib.compress(message)
decompressed = zlib.decompress(compressed)
print &＃39;original:&＃39;, repr(message)
print &＃39;compressed:&＃39;, repr(compressed)
print &＃39;decompressed:&＃39;, repr(decompressed)

结果

original: &＃39;abcd1234&＃39;
compressed: &＃39;x\x9cKLJN1426\x01\x00\x0b\xf8\x02U&＃39;
decompressed: &＃39;abcd1234&＃39;

例子2：压缩与解压文件

import zlib
def compress(infile, dst, level=9):
 infile = open(infile, &＃39;rb&＃39;)
 dst = open(dst, &＃39;wb&＃39;)
 compress = zlib.compressobj(level)
 data = infile.read(1024)
 while data:
  dst.write(compress.compress(data))
  data = infile.read(1024)
 dst.write(compress.flush())
def decompress(infile, dst):
 infile = open(infile, &＃39;rb&＃39;)
 dst = open(dst, &＃39;wb&＃39;)
 decompress = zlib.decompressobj()
 data = infile.read(1024)
 while data:
  dst.write(decompress.decompress(data))
  data = infile.read(1024)
 dst.write(decompress.flush())
if __name__ == "__main__":
 compress(&＃39;in.txt&＃39;, &＃39;out.txt&＃39;)
 decompress(&＃39;out.txt&＃39;, &＃39;out_decompress.txt&＃39;)

结果
生成文件

out_decompress.txt out.txt

问题――处理对象过大异常

>>> import zlib
>>> a = &＃39;123&＃39;
>>> b = zlib.compress(a)
>>> b
&＃39;x\x9c342\x06\x00\x01-\x00\x97&＃39;
>>> a = &＃39;a&＃39; * 1024 * 1024 * 1024 * 10
>>> b = zlib.compress(a)
Traceback (most recent call last):
 File "", line 1, in 
OverflowError: size does not fit in an int

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