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请帮忙解释一下,多表联查,小弟我看太不懂,谢啦

请帮忙解释一下,多表联查,我看太不懂,,谢啦SQLcodeselect*from(selectbookid,count(bookid)asdegreefromtb_borrowgroupbybookid)asborrjoin(selectb.*,c.nameasbookcasename,p.pubname,t.ty
请帮忙解释一下,多表联查,我看太不懂,,谢啦
SQL code
select * from (select bookid,count(bookid) as degree from tb_borrow group by bookid) as borr join (select b.*,c.name as bookcasename,p.pubname,t.typename from tb_bookinfo b left join tb_bookcase c on b.bookcase=c.id join tb_publishing p on b.ISBN=p.ISBN join tb_booktype t on b.typeid=t.id where b.del=0) as book on borr.bookid=book.id order by borr.degree desc limit 10 
请帮忙解释一下,多表联查,我看太不懂,,谢啦

------解决方案--------------------
SQL code

select * from 
    (
        select bookid,count(bookid) as degree from tb_borrow group by bookid
    )
as borr 
join 
      (
         select b.*,c.name as bookcasename,p.pubname,t.typename from tb_bookinfo b left join tb_bookcase c on b.bookcase=c.id join tb_publishing p on b.ISBN=p.ISBN join tb_booktype t on b.typeid=t.id where b.del=0
      ) 
as book on borr.bookid=book.id order by borr.degree desc limit 10 


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