探讨:使用XMLSerialize序列化与反序列化_PHP-php教程

概念：XML序列化是将公共字段和属性转化为序列格式（这里指XML），以便存储或传输的过程。反序列化则是从XML中重新创建原始状态的对象.
代码如下:
class SerializeDemo
{
static void Main()
{
EmployeeCollection employeeCollection = new EmployeeCollection()
{
Employees = Employeer.Employees()
};
XmlSerializer serialize = new XmlSerializer(typeof(EmployeeCollection));
string filePath = @"E:\PProject\Test\Employee.xml";
SerializeEmployee(serialize, filePath, employeeCollection);
DeserializeEmployee(serialize, filePath);
}
static void SerializeEmployee(XmlSerializer serialize, string filePath, EmployeeCollection employeeCollection)
{
using (FileStream fs = new FileStream(filePath, FileMode.Create, FileAccess.Write))
{
serialize.Serialize(fs, employeeCollection);
}
}
static void DeserializeEmployee(XmlSerializer serialize,string filePath)
{
using (FileStream fs = new FileStream(filePath, FileMode.Open, FileAccess.Read))
{
EmployeeCollection collection = (EmployeeCollection)serialize.Deserialize(fs);
collection.Employees.ForEach(e => Console.WriteLine("Name:{0},Gender:{1},Age:{2},Education:{3}", e.userName, e.gender, e.age, e.education));
}
}
}
[Serializable]
public class EmployeeCollection
{
public List Employees { get; set; }
}
[Serializable]
public class Employeer
{
public string userId { get; set; }
public string userName { get; set; }
public string gender { get; set; }
public int age { get; set; }
public List workExperience { get; set; }
public string education { get; set; }
public static List Employees()
{
return new List()
{
new Employeer()
{
userId = "0001",
userName = "guoHu",
gender="Man",
age=25,education="underGraduate",
workExperience = WorkExperience.GetWorkExperience("0001")
}
};

}
}
[Serializable]
public class WorkExperience
{
public string userId { get; set; }
public string companyName { get; set; }
public string seniority { get; set; }

public static List GetWorkExperience(string userId)
{
List workExperience = new List();
Unity unity = Unity.GetInstance();
DataTable table = new DataTable();
unity.GetTable(out table);

var experiences = (from experience in table.AsEnumerable()
where experience.Field("UserId") == userId
select new
{
companyName = experience.Field("CompanyName"),
seniority = experience.Field("Seniority")
}).ToList();
experiences.ForEach(e => workExperience.Add(new WorkExperience() { companyName = e.companyName, seniority = e.seniority }));
return workExperience;
}
}
public class Unity
{
public static DataTable tables = new DataTable();
public static DataRow dr;
public static DataColumn dc = new DataColumn();
public static object objLock = new object();
public static Unity unityInstance;
private Unity()
{

}
public static Unity GetInstance()
{
if (unityInstance == null)
{
lock (objLock)
{
if (unityInstance == null)
{
unityInstance = new Unity();
}
}
}
return unityInstance;
}
public void GetTable(out DataTable dt)
{
unityInstance.CreateTable();

dr = tables.NewRow();
dr["UserId"] = "0001";
dr["CompanyName"] = "WireSoft";
dr["Seniority"] = "2012.02-2012.05";
tables.Rows.Add(dr);
dr = tables.NewRow();
dr["UserId"] = "0001";
dr["CompanyName"] = "Jin Xun";
dr["Seniority"] = "2009.07-2011.02";
tables.Rows.Add(dr);
dr = tables.NewRow();
dr["UserId"] = "0002";
dr["CompanyName"] = "Hua Wei";
dr["Seniority"] = "2011.07-";
tables.Rows.Add(dr);
dt = tables.Copy();
}
public void CreateTable()
{
dc = new DataColumn("UserId", System.Type.GetType("System.String"));
tables.Columns.Add(dc);
dc = new DataColumn("companyName", System.Type.GetType("System.String"));
tables.Columns.Add(dc);
dc = new DataColumn("seniority", System.Type.GetType("System.String"));
tables.Columns.Add(dc);
}
}