文章介绍利用having group by 及各种select in 联合查询来实现的多种不同方法的过滤重复记录的sql语名。
1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断
| 代码如下 | |
| * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) |
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2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录
| 代码如下 | |
| delete from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1) |
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3、查找表中多余的重复记录（多个字段）
| 代码如下 | |
| select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) |
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4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录
| 代码如下 | |
| delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) |
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5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录
| 代码如下 | |
| select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1) |
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(二)
比方说
在A表中存在一个字段“name”，
而且不同记录之间的“name”值有可能会相同，
现在就是需要查询出在该表中的各记录之间，“name”值存在重复的项；
| 代码如下 | |
| Select Name,Count(*) From A Group By Name Having Count(*) > 1 |
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如果还查性别也相同大则如下:
| 代码如下 | |
| Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1 |
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(三)
方法一
| 代码如下 | |
| declare @max integer,@id integer declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >； 1 open cur_rows fetch cur_rows into @id,@max while @@fetch_status=0 begin select @max = @max -1 set rowcount @max delete from 表名 where 主字段 = @id fetch cur_rows into @id,@max end close cur_rows set rowcount 0 |
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方法二
有两个意义上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。
1、对于第一种重复，比较容易解决，使用
| 代码如下 | |
| select distinct * from tableName | |
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录（重复记录保留1条），可以按以下方法删除
| 代码如下 | |
| select distinct * into #Tmp from tableName drop table tableName select * into tableName from #Tmp drop table #Tmp |
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发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。
2、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下
假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集
| 代码如下 | |
| select identity(int,1,1) as autoID, * into #Tmp from tableName select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID select * from #Tmp where autoID in(select autoID from #tmp2) |
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最后一个select即得到了Name，Address不重复的结果集（但多了一个autoID字段，实际写时可以写在select子句中省去此列）
(四)查询重复
| 代码如下 | |
| select * from tablename where id in ( select id from tablename group by id having count(id) > 1 ) |
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