MySQL命令行删除表中的一个字段_MySQL

mysql> select * from test;
+------+--------+----------------------------------+------------+------------+------------+------------+
| t_id | t_name | t_password          | t_birth    | birth      | birth1     | birth2  |
+------+--------+----------------------------------+------------+------------+------------+------------+
|    1 | name1  | 12345678901234567890123456789012 | NULL     | 1990-01-01 | 0000-00-00 | 2013-01-01 |
|    2 | name2  | 12345678901234567890123456789012 | 2013-01-01 | NULL     | 0000-00-00 | 2013-01-01 |
+------+--------+----------------------------------+------------+------------+------------+------------+
2 rows in set (0.00 sec)

执行删除命令，使用drop关键字。
基本的语法为：alter table

<表名> drop column <字段名>;

具体的命令如下：

mysql> alter table test drop column birth1;
Query OK, 0 rows affected (0.13 sec)
Records: 0 Duplicates: 0 Warnings: 0

看看删除后的结果，是不是已经没有birth1字段了？

mysql> select * from test;
+------+--------+----------------------------------+------------+------------+------------+
| t_id | t_name | t_password | t_birth | birth | birth2 |
+------+--------+----------------------------------+------------+------------+------------+
| 1 | name1 | 12345678901234567890123456789012 | NULL | 1990-01-01 | 2013-01-01 |
| 2 | name2 | 12345678901234567890123456789012 | 2013-01-01 | NULL | 2013-01-01 |
+------+--------+----------------------------------+------------+------------+------------+
2 rows in set (0.00 sec)

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