正则表达式验证十六进制字符串-Regularexpressiontovalidatehexstring

51  

I believe

我相信

^([A-Fa-f0-9]{2}){8,9}$

will work.

将工作。

This is nice because it generalizes to any even-length string.

这很好，因为它可以推广到任何偶数长度的字符串。

9  

That's just a 16 character requirement with an optional 2 character afterwards:

这只是一个16个字符的要求，之后有一个可选的2个字符：

^[A-Fa-f0-9]{16}([A-Fa-f0-9]{2})?$

The parentheses may not be required - I'm not enough of a regex guru to know offhand, I'm afraid. If anyone wants to edit it, do feel free...

可能不需要括号 - 我不足以知道一个正则表达的大师，我害怕。如果有人想编辑它，请随意...

5  

^(?:[A-Fa-f0-9]{16}|[A-Fa-f0-9]{18})$

0  

I'd probably go with

我可能会去

/^[a-f0-9]{16}([a-f0-9]{2})?$/i

myself. I think it's more readable to set the regex as case insensitive and only list the character range once. That said, just about all of these answers work.

我。我认为将正则表达式设置为不区分大小写并且仅列出一次字符范围更具可读性。也就是说，几乎所有这些答案都有效。