在c中是否有一个函数可以复制char数组的特定部分-IsthereafunctionincwhereIcancopyspecificpartsofachararray

I have the char

我有炭

char test[] = "Hello there\n"
              "World, my name\n"
              "Is bob\n";

Is there a function where I can use to store each line into a different char array. So the \n would indicate for me to stop, and store it into a new array? So in the end I would have 3 sets of char arrays. Essentially is there a function which I can use to find the \n, then copy everything before it, but then stop copying if it sees a \n

是否有一个函数，我可以用来将每一行存储到一个不同的char数组。那么\ n会指示我停下来，并将其存储到一个新的数组中？所以最后我会有3组char数组。本质上是有一个函数，我可以用来找到\ n，然后复制它之前的所有内容，但如果它看到\ n然后停止复制\ n

char line1[] = "Hello there\n";
char line2[] = "World, my name\n";
char line3[] = "Is bob\n";

1 个解决方案

#include
#include
int main()
{
    char test[] = "Hello there\n"
              "World, my name\n"
              "Is bob\n";

    char *p;
    p = strtok(test, "\n");

    while(p) {
        printf("%s\n", p);
        p = strtok(NULL, "\n");
    }

    return 0;
}