运行在while循环中的代码期望输出-codesleepinginwhileloopexpecttheoutput

8  

This is the expected output:

这是预期输出:

• The program loops forever because of the while (1) loop.
• 由于while(1)循环，程序将永远循环。
• stdout is line-buffered (by default), so it only flushes to the console when a new-line character ('\n') is printed. As you aren't printing any new-line characters, you never see any of the hello-out text.
• stdout是行缓冲的(默认情况下)，因此只有在打印了新行字符('\n')时才会刷新到控制台。因为您没有打印任何新行字符，所以您永远不会看到任何helloout文本。
• However stderr is not line-buffered (by default), so it updates the console on every new fprintf() call.
• 但是stderr不是行缓冲的(默认情况下)，所以它在每个新的fprintf()调用上更新控制台。

5  

stdout is buffered on most machines. You won't see any output from any fprintf calls to stdout unless you print a newline or call fflush().

stdout在大多数机器上都有缓冲。除非您打印一个换行符或调用fflush()，否则不会看到来自任何fprintf调用stdout的输出。

So yes, it's expected behaviour, most of the time.

是的，大多数时候是预期行为。

4  

While everyone is right that you have an infinite loop, stderr is not buffered so you get it immediately, stdout is line buffered so it is deferred until you get a newline, they do not mention that stdout does not have infinite storage. I think the buffers are 1k or so by default (see setbuf). If you wait long enough you will get a very long burst of hello-out sequences. It is entirely possible that the last hello-out might be truncated part of the way through the string "hello-out".

虽然每个人都认为你有一个无限循环，但是stderr并没有缓冲，所以你马上就能得到它，stdout是行缓冲的，所以它被延迟，直到你得到一个换行符，他们没有提到stdout没有无限的存储空间。我认为默认的缓冲区是1k左右(参见setbuf)。如果你等待的时间足够长，你将会得到一长串hello-out序列。完全有可能最后的helloout通过字符串“helloout”被截断。

[...]hello-outhello-outhellhello-errhello-err
                       ^^^^