Swift初始化器中参数名称使用"with"的规范与最佳实践分析

This initialiser will cause an error complaining that "with" is implied for the first parameter of an initialiser; did you mean name?

此初始化程序将导致错误,抱怨初始化程序的第一个参数隐含“with”;你是说名字吗?

init(withName: String){

}

I'm not sure what this means, if it provides automagically the withName external parameter name if I call it name or what...

我不确定这意味着什么,如果我自动提供withName外部参数名称,如果我称之为名称或什么...

If I change it to

如果我改成它

init(name: String){

}

any attempt at calling it init(with: "joe") or init(withName: "Joe") will fail. So I have no idea what the error message is telling me and how I can declare it so I call it init(withName: "joe").

任何调用init(使用:“joe”)或init(withName:“Joe”)的尝试都将失败。所以我不知道错误消息告诉我什么以及我如何声明它所以我称之为init(withName:“joe”)。

1 个解决方案