做个万年历，有谁知道农历日期与阳历日期的对应关系，呵呵借宝地了

给你一我收藏的^_^

 前段时间做软件写了个公历转农历的函数,目前公开给大家参考,有兴趣的朋友可以在此基础上进一步完善其功能

/*------------农历转换函数-----------*/
char *GetDayOf(PSYSTEMTIME pSt)
{ 
 /*天干名称*/
 const char *cTianGan[] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
 /*地支名称*/
 const char *cDiZhi[] = {"子","丑","寅","卯","辰","巳","午",
       "未","申","酉","戌","亥"};
 /*属相名称*/
 const char *cShuXiang[] = {"鼠","牛","虎","兔","龙","蛇",
       "马","羊","猴","鸡","狗","猪"};
 /*农历日期名*/
 const char *cDayName[] = {"*","初一","初二","初三","初四","初五",
       "初六","初七","初八","初九","初十",
       "十一","十二","十三","十四","十五",
       "十六","十七","十八","十九","二十",
       "廿一","廿二","廿三","廿四","廿五",       
       "廿六","廿七","廿八","廿九","三十"};
 /*农历月份名*/
 const char *cMonName[] = {"*","正","二","三","四","五","六",
       "七","八","九","十","十一","腊"};

 /*公历每月前面的天数*/
 const int wMonthAdd[12] = {0,31,59,90,120,151,181,212,243,273,304,334};
 /*农历数据*/
 const int wNongliData[100] = {2635,333387,1701,1748,267701,694,2391,133423,1175,396438
       ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402
       ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738
       ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762
       ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413
       ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395
       ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031
       ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222
       ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709
       ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877};
 static int wCurYear,wCurMonth,wCurDay;
 static int nTheDate,nIsEnd,m,k,n,i,nBit;
 TCHAR szNongli[30], szNongliDay[10],szShuXiang[10];
 /*---取当前公历年、月、日---*/
 wCurYear = pSt->wYear;
 wCurMonth = pSt->wMonth;
 wCurDay = pSt->wDay;
 /*---计算到初始时间1921年2月8日的天数：1921-2-8(正月初一)---*/
 nTheDate = (wCurYear - 1921) * 365 + (wCurYear - 1921) / 4 + wCurDay + wMonthAdd[wCurMonth - 1] - 38;
 if((!(wCurYear % 4)) && (wCurMonth > 2))
  nTheDate = nTheDate + 1;

 /*--计算农历天干、地支、月、日---*/
 nIsEnd = 0;
 m = 0;
 while(nIsEnd != 1)
 {
  if(wNongliData[m] < 4095)
   k = 11;
  else
   k = 12;
  n = k;
  while(n>=0)
  {
   //获取wNongliData(m)的第n个二进制位的值
   nBit = wNongliData[m];
   for(i=1;i     nBit = nBit/2;

   nBit = nBit % 2;

   if (nTheDate <= (29 + nBit))
   {
    nIsEnd = 1;
    break;
   }

   nTheDate = nTheDate - 29 - nBit;
   n = n - 1;
  }
  if(nIsEnd)
   break;
  m = m + 1;
 }
 wCurYear = 1921 + m;
 wCurMonth = k - n + 1;
 wCurDay = nTheDate;
 if (k == 12)
 {
  if (wCurMonth == wNongliData[m] / 65536 + 1)
   wCurMonth = 1 - wCurMonth;
  else if (wCurMonth > wNongliData[m] / 65536 + 1)
   wCurMonth = wCurMonth - 1;
 }

 /*--生成农历天干、地支、属相 ==> wNongli--*/
 wsprintf(szShuXiang,"%s",cShuXiang[((wCurYear - 4) % 60) % 12]);
 wsprintf(szNongli,"%s(%s%s)年",szShuXiang,cTianGan[((wCurYear - 4) % 60) % 10],cDiZhi[((wCurYear - 4) % 60) % 12]);

 /*--生成农历月、日 ==> wNongliDay--*/
 if (wCurMonth < 1)
  wsprintf(szNongliDay,"闰%s",cMonName[-1 * wCurMonth]);
 else
  strcpy(szNongliDay,cMonName[wCurMonth]);

 strcat(szNongliDay,"月");
 strcat(szNongliDay,cDayName[wCurDay]);
 return strcat(szNongli,szNongliDay);

}

不知道，进来了就帮你顶一下

:)3Q
我仔细研究一下

啊，哈哈，答案已经出来了，不好意，那我也收藏一份，谢谢！！！

谢谢 hcj2002(流浪者) 
农历数据那张表的年份范围 有没有更大的

VC有控件得嘛

抱歉提醒二楼一下，那个代码仔细看有错误的日期。

好像没有错误啊，楼上你说的错误是哪啊
是农历数组吗？

我是说，换算出的有的日期不正确。

if((!(wCurYear % 4)) && (wCurMonth > 2))
  nTheDate = nTheDate + 1;
我想应该是这句错了，闰年的判断(iYear % 4) && (iYear % 100) || !(iYear % 400);