作者:刘德华 | 来源:互联网 | 2024-09-24 17:57
我目前正在制作一个子手程序,但被卡住了.每当我为单词输入正确的猜测时,我都会不断收到错误的“str”对象不支持项目分配.这是我的代码:importrandomdefdisplayB
我目前正在制作一个子手程序,但被卡住了.每当我为单词输入正确的猜测时,我都会不断收到错误的“ str”对象不支持项目分配.
这是我的代码:
import random
def displayBoard(randomWord):
board = []
for i in randomWord:
board.append(' _ ')
return ''.join(board)
def gameGuesses(randomWord):
newBoard = displayBoard(randomWord)
print(newBoard)
mistakes = 6
count = 0
while not False and mistakes > 0:
letterInput = input("\nPlease input a letter: ").upper()
if letterInput in randomWord:
letter = randomWord.index(letterInput)
while count != letter:
count += 1
if count == letter:
>>>newBoard[count] = letterInput<<<#PROBLEM
else:
mistakes = mistakes - 1
print("Incorrect letter.",mistakes,"remaining.")
wordList = ["Python","Hello","Random"]
randomWord = random.choice(wordList).upper()
gameGuesses(randomWord)
问题出在newBoard [count] = letterInput.我应该如何用输入的正确字母替换下划线?
解决方法:
newBoard是一个字符串,并且字符串在Python中是不可变的-这就是为什么不允许项目分配.
您必须构建一个新字符串.例如,如果您想替换“ helloworld”中第4位(o)处的字符,则会发出
>>> s = 'helloworld'
>>> s = s[:4] + 'X' + s[5:]
>>> s
'hellXworld'
另一种选择是使用字节数组:
>>> s = bytearray('helloworld')
>>> print(s)
helloworld
>>> s[4] = 'X'
>>> print(s)
hellXworld