JqueryUI滑块，设置值bug-JqueryUIslider,settingvaluesbug

5  

have you tried:

你有没有尝试过:

$('selector').slider( 'values' , index , value ); // index would be the square in the slider

in your example you could:

在你的例子中你可以:

$("#slider-range1").slider('values', 0, 50);
$("#slider-range1").slider('values', 1, 100);

1  

$('#slider-range').slider('option', 'min', 1);

$('#slider-range')。slider('option','min',1);

$('#slider-range').slider('option', 'max', 100);

$('#slider-range')。slider('option','max',100);

Updated according to poster's comment on this answer:

根据海报对此答案的评论更新:

Actually, your question contains an naswer :)

实际上,你的问题包含了一个问题:)

http://jqueryui.com/demos/slider/#option-range

$("#slider-range").slider({
    range: true,
    min: 0,
    max: 500,
    values: [75, 300],
});