作者：Ericke2702932972 | 来源：互联网 | 2024-09-30 16:59
可以通过Gson使用两种方法，将json字符串转换为对象，以下面该段报文做测试
{
"id": 84041462,
"lastName": "小华",
"age":32,
"balance":666255.32,
"hobbyDesc": {
"subject": "数学",
"score":25,
"sport_desc":"跑步有益健康"
}
}
1. 创建实体类，通过 fromJson方法将json数据封装进对象中
如上，将上面报文按层次解析并创建两个对象
import com.google.gson.annotations.SerializedName;
public class HobbyDesc {
private String subject;
private int score;
@SerializedName("sport_desc")
private String sportDesc;
//***
public class Account {
private String id;
private String lastName;
private int age;
private double balance;
private HobbyDesc hobbyDesc;
//***
解析
String jsOnStr= "{\n" +
"\t\"id\": 84041462,\n" +
"\t\"lastName\": \"小华\",\n" +
"\t\"age\":32,\n" +
"\t\"balance\":666255.32,\n" +
"\t\"hobbyDesc\": {\n" +
"\t\t\"subject\": \"数学\",\n" +
"\t\t\"score\":25,\n" +
"\t\t\"sport_desc\":\"跑步有益健康\"\n" +
"\t}\n" +
"\t\n" +
"}";
Account account = new Gson().fromJson(jsonStr,Account.class);
同时也可以看到，对象中定义为字符串类型的字段也可以接受json串的数值类型，没有转换问题。
2. 解析为jsonObject对象
直接使用Gson API解析
String jsOnStr= "{\n" +
"\t\"id\": 84041462,\n" +
"\t\"lastName\": \"小华\",\n" +
"\t\"age\":32,\n" +
"\t\"balance\":666255.32,\n" +
"\t\"hobbyDesc\": {\n" +
"\t\t\"subject\": \"数学\",\n" +
"\t\t\"score\":25,\n" +
"\t\t\"sport_desc\":\"跑步有益健康\"\n" +
"\t}\n" +
"\t\n" +
"}";
JsonObject jsonObject = (JsonObject) new JsonParser().parse(jsonStr);
System.out.println("id = "+jsonObject.get("id").getAsInt());//id = 84041462
System.out.println("id = "+jsonObject.get("id").getAsString());//id = 84041462
System.out.println("position = "+ jsonObject.get("hobbyDesc").getAsJsonObject().get("sport_desc").getAsString());//position = 跑步有益健康
参照jsonObject结构，可以了解Gson这种封装对象的方式，如果仅仅是取某值的话，可以采用这种方式，可以节约大量时间
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