C#各种地图坐标系的转换

一个人可能被剥夺一切，但他在任何情况下选择自己的态度和方式的自由无法被剥夺，这是人类最后的自由。
3 private static double pi = 3.1415926535897932384626;
4 private static double a = 6378245.0;
5 private static double ee = 0.00669342162296594323;
6 private static double bd_pi = 3.14159265358979324 * 3000.0 / 180.0;
8 static Boolean outOfChina(double lat, double lon)
10 if (lon 72.004 || lon 137.8347)
11 return true;
12 if (lat 0.8293 || lat 55.8271)
13 return true;
14 return false;
15 }
17 static double transformLat(double x, double y)
18 {
19 double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y
20 + 0.2 * Math.Sqrt(Math.Abs(x));
21 ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
22 ret += (20.0 * Math.Sin(y * pi) + 40.0 * Math.Sin(y / 3.0 * pi)) * 2.0 / 3.0;
23 ret += (160.0 * Math.Sin(y / 12.0 * pi) + 320 * Math.Sin(y * pi / 30.0)) * 2.0 / 3.0;
24 return ret;
25 }
27 static double transformLon(double x, double y)
28 {
29 double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1
30 * Math.Sqrt(Math.Abs(x));
31 ret += (20.0 * Math.Sin(6.0 * x * pi) + 20.0 * Math.Sin(2.0 * x * pi)) * 2.0 / 3.0;
32 ret += (20.0 * Math.Sin(x * pi) + 40.0 * Math.Sin(x / 3.0 * pi)) * 2.0 / 3.0;
33 ret += (150.0 * Math.Sin(x / 12.0 * pi) + 300.0 * Math.Sin(x / 30.0
34 * pi)) * 2.0 / 3.0;
35 return ret;
36 }
38 /**
39 * 84 to 火星坐标系 (GCJ-02) World Geodetic System == Mars Geodetic System
40 *
41 * @param lat
42 * @param lon
43 * @return
44 */
46 public static PointLatLng gps84_To_Gcj02(PointLatLng Gpoint)
47 {
48 if (outOfChina(Gpoint.Lat, Gpoint.Lng))
49 {
50 return new PointLatLng(0, 0);
51 }
52 double dLat = transformLat(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0);
53 double dLon = transformLon(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0);
54 double radLat = Gpoint.Lat / 180.0 * pi;
55 double magic = Math.Sin(radLat);
56 magic = 1 - ee * magic * magic;
57 double sqrtMagic = Math.Sqrt(magic);
58 dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
59 dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
60 double mgLat = Gpoint.Lat + dLat;
61 double mgLon = Gpoint.Lng + dLon;
62 return new PointLatLng(mgLat, mgLon);
63 }
64 static PointLatLng transform(PointLatLng Gpoint)
65 {
66 if (outOfChina(Gpoint.Lat, Gpoint.Lng))
67 {
68 return new PointLatLng(Gpoint.Lat, Gpoint.Lng);
69 }
70 double dLat = transformLat(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0);
71 double dLon = transformLon(Gpoint.Lng - 105.0, Gpoint.Lat - 35.0);
72 double radLat = Gpoint.Lat / 180.0 * pi;
73 double magic = Math.Sin(radLat);
74 magic = 1 - ee * magic * magic;
75 double sqrtMagic = Math.Sqrt(magic);
76 dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
77 dLon = (dLon * 180.0) / (a / sqrtMagic * Math.Cos(radLat) * pi);
78 double mgLat = Gpoint.Lat + dLat;
79 double mgLon = Gpoint.Lng + dLon;
80 return new PointLatLng(mgLat, mgLon);
81 }
83 /**
84 * * 火星坐标系 (GCJ-02) to 84 * * @param lon * @param lat * @return
85 * */
86 public static PointLatLng gcj02_To_Gps84(PointLatLng Gpoint)
87 {
88 PointLatLng gps = transform(Gpoint);
89 double lOntitude= Gpoint.Lng * 2 - gps.Lng;
90 double latitude = Gpoint.Lat * 2 - gps.Lat;
91 return new PointLatLng(latitude, lontitude);
92 }
93 /**
94 * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 将 GCJ-02 坐标转换成 BD-09 坐标
95 *
96 * @param gg_lat
97 * @param gg_lon
98 */
99 public static PointLatLng gcj02_To_Bd09(PointLatLng Gpoint)
100 {
101 double x = Gpoint.Lng, y = Gpoint.Lat;
102 double z = Math.Sqrt(x * x + y * y) + 0.00002 * Math.Sin(y * bd_pi);
103 double theta = Math.Atan2(y, x) + 0.000003 * Math.Cos(x * bd_pi);
104 double bd_lon = z * Math.Cos(theta) + 0.0065;
105 double bd_lat = z * Math.Sin(theta) + 0.006;
106 return new PointLatLng(bd_lat, bd_lon);
107 }
109 /**
110 * * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 * * 将 BD-09 坐标转换成GCJ-02 坐标 * * @param
111 * bd_lat * @param bd_lon * @return
112 */
113 public static PointLatLng bd09_To_Gcj02(PointLatLng bdPoint)
114 {
115 double x = bdPoint.Lng - 0.0065, y = bdPoint.Lat - 0.006;
116 double z = Math.Sqrt(x * x + y * y) - 0.00002 * Math.Sin(y * bd_pi);
117 double theta = Math.Atan2(y, x) - 0.000003 * Math.Cos(x * bd_pi);
118 double gg_lon = z * Math.Cos(theta);
119 double gg_lat = z * Math.Sin(theta);
120 return new PointLatLng(gg_lat, gg_lon);
121 }
123 /**
124 * (BD-09)-- 84
125 * @param bd_lat
126 * @param bd_lon
127 * @return
128 */
129 public static PointLatLng bd09_To_Gps84(PointLatLng bdPoint)
130 {
132 PointLatLng gcj02 = bd09_To_Gcj02(bdPoint);
133 PointLatLng map84 = gcj02_To_Gps84(gcj02);
134 return map84;
136 }
137 /**
138 * 84-- (BD-09)
139 * @param bd_lat
140 * @param bd_lon
141 * @return
142 */
143 public static PointLatLng Gps84_To_bd09(PointLatLng gpsPoint)
144 {
145 PointLatLng gcj02 = gps84_To_Gcj02(gpsPoint);
146 PointLatLng bd09 = gcj02_To_Bd09(gcj02);
147 return bd09;
149 }
151 }
153 public class PointLatLng
154 {
156 public PointLatLng(double lat, double lng)
157 {
158 Lat = lat;
159 Lng = lng;
160 }
161 public double Lat { get; set; }
162 public double Lng { get; set; }
163 }

文章来源于https://www.cnblogs.com/Lxk0825/p/15465944.html