C++实现浮点数精确加法

int main(){
 char num1[128],num2[128],res[128];
 cout<<"Enter the first number:";
 cin>>num1;
 cout<<"Enter the second number:";
 cin>>num2;
 add(num1,num2,res);
 cout<

#include 

using namespace std;

void add(char num1[], char num2[], char res[]);

int get_len(char num[]);

int get_integer(char num[]);

int get_dot(char num[]);

int get_decimal_len(char num[]);

int get_integer_len(int x);

int char_to_int(char num[], int begin, int len);

void int_to_char(char res[], int x);

void get_decimal(char num1[], char num2[]);

char decimal[128] = {0};

int main() {
 char num1[128] = {0}, num2[128] = {0}, res[128] = {0};
 cout <<"Enter the first number:";
 cin >> num1;
 cout <<"Enter the second number:";
 cin >> num2;
 add(num1, num2, res);
 cout <= 0; --i) {
 res[i] = x % 10 + '0';
 x /= 10;
 }
 res[l + 1] = '\0';
}

//得到整数部分
int get_integer(char num[]) {
 int integer = 0, x = get_dot(num);
 for (int i = 0; i <= x - 1; ++i) {
 integer = integer * 10 + num[i] - '0';
 }
 return integer;
}

//得到小数部分长度
int get_decimal_len(char num[]) {
 int x = get_dot(num), len = 0;
 for (int i = x + 1; num[i] != '\0'; ++i)len++;
 return len;
}

//得到整数的长度
int get_integer_len(int x) {
 int integer_len = 0;
 if (x == 0)return 1;
 while (x > 0) {
 x /= 10;
 integer_len++;
 }
 return integer_len;
}

//得到字符串长度
int get_len(char num[]) {
 int sum = 0;
 for (int i = 0; num[i] != '\0'; ++i) sum++;
 return sum;
}

//得到小数变成整数后的和
void get_decimal(char num1[], char num2[]) {
 int decimal_len = get_decimal_len(num1) > get_decimal_len(num2) &＃63; get_decimal_len(num1) : get_decimal_len(num2);
 int decimal_sum = char_to_int(num1, get_dot(num1), decimal_len) + char_to_int(num2, get_dot(num2), decimal_len);
 int_to_char(decimal, decimal_sum);
 if (decimal_len  get_decimal_len(num2) &＃63; get_decimal_len(num1) : get_decimal_len(num2);
 int decimal_sum = char_to_int(num1, get_dot(num1), decimal_len) + char_to_int(num2, get_dot(num2), decimal_len);
 if (decimal_len  get_dot(res); --i) {
 if (res[i] == '0') {
 res[i] = '\0';
 break;
 }
 break;
 }
 }
 num1[l1] = '\0', num2[l2] = '\0';
}