C++和Java命令行绘制心形图案

#include 
#include 

using namespace std;

#define X_DIVIDED_BY_Y 0.5
#define MAX_X (35.0 / X_DIVIDED_BY_Y)
#define MAX_Y 35.0
#define THRESHOLD 0.5
#define A 13

char getSentenceChar(const char *sentence, int &index) {
 while(true) {
  if (index >= strlen(sentence)) {
   index = 0;
  }
  char c = sentence[index++];
  if(' ' == c) {
   index++;
  } else {
   return c;
  }
 }
}

inline float getX(float x) {
 return (x - MAX_X / 2) * X_DIVIDED_BY_Y;
}

inline float getY(float y) {
 return MAX_Y / 7.0 - y;
}

bool func(float x, float y) {
 return (pow(x, 2) + pow(y, 2) + A * x - A * sqrt(pow(x, 2) + pow(y, 2))) 

package com.example.demo;

public class BenevolenceDemo {

 private static final float X_DIVIDED_BY_Y = 0.5f;
 private static final float MAX_X = 35f / X_DIVIDED_BY_Y;
 private static final float MAX_Y = 35f;
 private static final float THRESHOLD = 0.5f;
 private static final float A = 13;
 private static final String LOVE_SENTENCE = "No rose, no diamond ring, that is the simple and romantic love stories in college. The graduates have to face the approaching of June, a time to farewell their beloved. When their future is confronted with love, which one is more important&＃63; What will the lovers do in June&＃63;";
 private static int sentenceIndex = 0;

 private static char getSentenceChar() {
  while(true) {
   if (sentenceIndex >= LOVE_SENTENCE.length()) {
    sentenceIndex = 0;
   }
   char c = LOVE_SENTENCE.charAt(sentenceIndex++);
   if(' ' == c) {
    sentenceIndex++;
   } else {
    return c;
   }
  }
 }

 public static void main(String[] args) {
  for (int y = 0; y <= MAX_Y; y++) {
   for (int x = 0; x <= MAX_X; x++) {
    System.out.print(func(getY(y), getX(x)) &＃63; getSentenceChar() : '=');
   }
   System.out.println();
  }
 }

 public static final float getX(float x) {
  return (x - MAX_X / 2) * X_DIVIDED_BY_Y;
 }

 public static final float getY(float y) {
  return MAX_Y / 7f - y;
 }

 public static boolean func(float x, float y) {
  return (Math.pow(x, 2) + Math.pow(y, 2) + A * x - A * Math.sqrt(Math.pow(x, 2) + Math.pow(y, 2)))