作者：Effy | 来源：互联网 | 2013-04-22 17:17
PHP代码============================$array=array('username'=>'杨铸','password'=>'123456',&
PHP代码============================
$array = array(
&＃39;username&＃39;=>&＃39;杨铸&＃39;,
&＃39;password&＃39;=>&＃39;123456&＃39;,
&＃39;user_id&＃39;=>1
);
echo json_encode($array);
Java代码============================
private void startUrlCheck(String username,String password)
{
HttpClient client = new DefaultHttpClient();
StringBuilder builder = new StringBuilder();
HttpGet myget = new HttpGet("http://10.0.2.2/Android/index.php");
try {
HttpResponse respOnse= client.execute(myget);
BufferedReader reader = new BufferedReader(new InputStreamReader(
response.getEntity().getContent()));
for (String s = reader.readLine(); s != null; s = reader.readLine()) {
builder.append(s);
}
JSONObject jsOnObject= new JSONObject(builder.toString());
String re_username = jsonObject.getString("username");
String re_password = jsonObject.getString("password");
int re_user_id = jsonObject.getInt("user_id");
setTitle("用户id_"+re_user_id);
Log.v("url response", "true="+re_username);
Log.v("url response", "true="+re_password);
} catch (Exception e) {
Log.v("url response", "false");
e.printStackTrace();
}
}
运行结果===================================
其中http://10.0.2.2为Android访问本机url的ip地址。对应电脑上测试的http://127.0.0.1
另外执行代码时会抛出异常PHP100.com
java.net.SocketException: Permission denied
此为应用访问网络的权限不足 在AndroidManifest.xml中，需要进行如下配置：
就加在
之前就好了
然后测试通过。
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