我们递归地搞 使得包含点P的某个仙人掌被构造出来且除了P是1其他都是2
然后就是拆桥边或拆环 递归下去 然后在合起来就行了
把桥边接起来很显然 环的话 自己画画也不难搞出来了吧
#include
#include
#include
#include
#include
#define pb push_back
using namespace std;
typedef pair<int,int> abcd;
inline char nc(){
static char buf[100000],*p1=buf,*p2=buf;
return p1==p2&&(p2=(p1=buf)+fread(buf,1,100000,stdin),p1==p2)?EOF:*p1++;
}
inline void read(int &x){
char c=nc(),b=1;
for (;!(c>='0' && c<='9');c=nc()) if (c=='-') b=-1;
for (x=0;c>='0' && c<='9';x=x*10+c-'0',c=nc()); x*=b;
}
const int N=50005;
set Set;
struct edge{
int u,v,next;
}G[N<<2];
int head[N],inum=1;
int cur[N];
inline void add(int u,int v,int p){
G[p].u=u; G[p].v=v; G[p].next=head[u]; head[u]=p;
}
inline void Add(int u,int v){
if (u>v) swap(u,v); if (!Set.count(abcd(u,v))) add(u,v,++inum),add(v,u,++inum),Set.insert(abcd(u,v));
}
#define V G[p].v
int n,m,cnt;
int cir[N<<2],depth[N],fap[N],fat[N];
inline void dfs(int u,int fa){
depth[u]=depth[fa]+1; fat[u]=fa;
for (int p=head[u];p;p=G[p].next)
if (V!=fa)
if (!depth[V])
fap[V]=p,dfs(V,u);
else if (depth[V]int t=u; ++cnt;
while (t!=V) cir[fap[t]]=cir[fap[t]^1]=cnt,t=fat[t];
cir[p]=cir[p^1]=cnt;
}
}
int del[N<<2];
struct info{
char f; int x,y,z;
info(char f,int x,int y,int z=0):f(f),x(x),y(y),z(z) { }
};
vector Ans;
#define J(x,y) (Ans.pb(info('j',x,y)))
#define R(x,y,z) (Ans.pb(info('r',x,y,z)))
#define C(x,y,z) (Ans.pb(info('c',x,y,z)))
inline void Solve(int u){
int ed=0;
for (int p=cur[u];p;p=G[p].next)
if (!del[p]){
ed=p; break;
}
cur[u]=ed;
if (!ed) return;
del[ed]=del[ed^1]=1;
int v=G[ed].v;
if (!cir[ed]){
Solve(u); Solve(v);
R(v,1,3); J(u,v); C(u,1,3); R(u,3,2);
return;
}
vector<int> path;
path.pb(u); path.pb(v); int cur=v;
while (1){
int p;
for (p=head[cur];p;p=G[p].next)
if (cir[p]==cir[ed] && !del[p])
break;
del[p]=del[p^1]=1;
if (V==u) break;
path.pb(V); cur=V;
}
for (int x:path)
Solve(x);
R(v,1,3); J(u,v); C(u,1,3);
int last=v;
for (int i=2;i<(int)path.size();i++){
int x=path[i];
R(x,1,4); J(last,x); C(x,3,4); R(x,3,2); R(x,4,3);
last=x;
}
C(u,1,3); R(u,3,2);
}
int main(){
int x,y,k;
freopen("cactus.in","r",stdin);
freopen("cactus.out","w",stdout);
read(n); read(m);
while (m--){
read(k); read(x);
for (int i=2;i<=k;i++)
read(y),Add(x,y),x=y;
}
dfs(1,0);
for (int i=1;i<=n;i++) cur[i]=head[i];
Solve(1);
printf("%d\n",(int)Ans.size());
for (info x:Ans)
if (x.f=='j')
printf("%c %d %d\n",x.f,x.x,x.y);
else
printf("%c %d %d %d\n",x.f,x.x,x.y,x.z);
return 0;
}