在java中以MB读取大文件的最佳方法

我正在阅读帖子,它说使用BufferedReader或MappedByteBuffer.我决定用291.0 MB文件自己测试,但仍然无法决定

    BufferedReader reader = new BufferedReader(new FileReader("/Users/rachana/part-00000"));
    String line = null;
    while((line = reader.readLine())!=null) {
        System.out.println(line);
    }


    ~~~~~~ Heap utilization in MB ~~~~~~
    Start Date  21:10:20
    End Date 21:17:48
    Time used 448 second
           7.50 min
    Used Memory In MB:28
    Free Memory:81
    Total Memory:109
    Max Memory:1820

使用MappedByteBuffer

RandomAccessFile aFile = new RandomAccessFile
                ("/Users/rachana/part-00000", "r");
        FileChannel inChannel = aFile.getChannel();
        MappedByteBuffer buffer = inChannel.map(FileChannel.MapMode.READ_ONLY, 0, inChannel.size());
        buffer.load(); 
        for (int i = 0; i < buffer.limit(); i++)
        {
            System.out.print((char) buffer.get());
        }
        buffer.clear(); // do something with the data and clear/compact it.
        inChannel.close();
        aFile.close();



~~~~~~ Heap utilization in MB ~~~~~~
 Start Date  21:20:40
 End Date 21:33:52
 Time used 792 sec / 13.2 min
Used Memory In MB:4 
Free Memory:104
Total Memory:109
Max Memory:1820

它清楚地表明MappedByteBuffer使用更少的内存,但更多的时间,因为BufferedReader使用更多的内存但更少的时间.

我试图找到平衡也使用MappedByteBuffer读取行.

任何建议都会有所帮助