问

在for循环中声明多个函数

mobiledu2502889793 发布于 2023-02-06 17:10

http

java

图片

html

我正在创建一个图像库,其缩略图类似于http://coolcarousels.frebsite.nl/c/28/.我有它正常工作,但我希望使用for循环缩短我的JavaScript代码,因为我将使用25张图片.

我的HTML代码中有以下摘录:

从我的JavaScript代码:

var imgNumber = 0;
var NumberOfImages = 6-1; //-1 because array members starts from 0

//Images 
var img = new Array(NumberOfImages);

img[0] = "images/Taj Mahal.jpg";
img[1] = "images/India01.jpg"; 
img[2] = "images/India02.jpg"; 
img[3] = "images/India03.jpg"; 
img[4] = "images/India04.jpg";
img[5] = "images/India05.jpg";

//Captions   
var imgcap = new Array(NumberOfImages);

imgcap[0] = "Taj Mahal, Agra";
imgcap[1] = "Driving through Delhi";
imgcap[2] = "India Gate, Delhi";
imgcap[3] = "Lotus Temple, Delhi";
imgcap[4] = "Monkeys fighting in the streets of Delhi!"; 
imgcap[5] = "Old Delhi";

function changeImage0()
{
    x=document.getElementById('myimage')
    imgNumber=0;
    x.src=img[imgNumber];
    x=document.getElementById("cap");
    x.innerHTML=imgcap[imgNumber];
}
function changeImage1()
{
    x=document.getElementById('myimage')
    imgNumber=1;
    x.src=img[imgNumber];
    x=document.getElementById("cap");
    x.innerHTML=imgcap[imgNumber];
}
function changeImage2()
{
    x=document.getElementById('myimage')
    imgNumber=2;
    x.src=img[imgNumber];
    x=document.getElementById("cap");
    x.innerHTML=imgcap[imgNumber];
}
function changeImage3()
{
    x=document.getElementById('myimage')
    imgNumber=3;
    x.src=img[imgNumber];
    x=document.getElementById("cap");
    x.innerHTML=imgcap[imgNumber];
}
function changeImage4()
{
    x=document.getElementById('myimage')
    imgNumber=4;
    x.src=img[imgNumber];
    x=document.getElementById("cap");
    x.innerHTML=imgcap[imgNumber];
}
function changeImage5()
{
    x=document.getElementById('myimage')
    imgNumber=5;
    x.src=img[imgNumber];
    x=document.getElementById("cap");
    x.innerHTML=imgcap[imgNumber];
}

正如您所看到的,我希望使用6个不同的名称声明6个不同的函数,但是因为它们都执行类似的角色,所以我想使用for循环来执行此声明

for(var d=0;d<=NumberOfImages;d++)
{
    function changeImage(d)
    {
        x=document.getElementById('myimage');
        imgNumber=d
        x.src=img[imgNumber];
        x=document.getElementById("cap");
        x.innerHTML=imgcap[imgNumber];
    }
}

但不幸的是,我不能让这个工作.我有一种感觉,我可能会使用"function changeImage(d)"错误地声明函数.这是错的吗？关于如何创建将创建我的函数的循环的任何想法:changeImage0,changeImage1,changeImage2,...提前感谢!

1 个回答

不,您不必声明多个功能.一个没关系:

function changeImage(d)
{
    x = document.getElementById('myimage');
    imgNumber = d;
    x.src = img[imgNumber];
    x = document.getElementById("cap");
    x.innerHTML = imgcap[imgNumber];
}

甚至更好:

function changeImage(d)
{
    document.getElementById('myimage').src = img[d];
    document.getElementById("cap").innerHTML = imgcap[d];
}

并像这样使用它:

<img src="thumbs/Taj Mahal_thumb.jpg" onclick="changeImage(0)">
<img src="thumbs/India01_thumb.jpg" onclick="changeImage(1)">
<img src="thumbs/India02_thumb.jpg" onclick="changeImage(2)">
<img src="thumbs/India03_thumb.jpg" onclick="changeImage(3)">
<img src="thumbs/India04_thumb.jpg" onclick="changeImage(4)">

2023-02-06 17:13 回答

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