为什么用new创建的C++数组的行为与C风格数组不同？

我正在自学C++,因此一直在编写一些示例代码来真正指出我对指针和数组的理解.

我写了这个:

int myints[] = {20, 40, 60, 80, 100}; 
// C style array? should be stored on stack? is myint's type pointer to int or an array of int? how does it differ from myotherints?

int* myotherints = new int[5]{20, 40, 60, 80, 100}; // new always returns pointer, is this a C++ style array?     
// does this pointer get created on stack while the elements themselves are created in free heap?

int j = 5; // should be stored on stack

cout << "myints: " << myints << endl; // decays to pointer, shows address array myints is stored at
cout << "*myints: " << *myints << endl; // myints decays to pointer and is dereferenced to return value stored at start of array myints
cout << "myints[0]: " << myints[0] << endl; // [] dereferences and returns value for element 0 (20)
cout << "myotherints: " << myotherints << endl; // some value?? this is totally unlike the others, why? what is this?
cout << "*myotherints: " << *myotherints << endl; // dereferences pointer myotherints to get address that holds value 20 for first element
cout << "myotherints[0]: " << myotherints[0] << endl; // [] dereferences pointer to get address that holds value 20 for first element
cout << "j: " << j << endl << endl; // 5, sure

cout << "&myints: " << &myints << endl; // array behaving as pointer, gives address of myints[0]
cout << "&myints[0]: " << &myints[0] << endl; // array behaving as pointer, gives address of myints[0]
cout << "&myotherints: " << &myotherints << endl; // address of myotherints, is this where the pointer to the array is stored?
cout << "&myotherints[0]: " << &myotherints[0] << endl; // [] dereferences the pointer that myotherints points to and returns element 0
cout << "&j: " << &j << endl; // address of j

/*
myints: 0x7fff096df830 <-- this makes sense to me, array decays to pointer to give first element address
*myints: 20            <-- this makes sense to me, dereference first element address for value
myints[0]: 20          <-- [] dereferences implicitly, returns value from pointer

myotherints: 0x2308010 <-- myotherints is a pointer to an array of ints, but its address is much lower compared to myints and j, why is that?
*myotherints: 20       <-- getting the value from above address returns 20
myotherints[0]: 20     <-- [] dereferences to address pointed to by pointer myotherints, returns value

j: 5

&myints: 0x7fff096df830      <-- same as below
&myints[0]: 0x7fff096df830   <-- same as above, meaning *myints and myints[0] are the same thing, this address

&myotherints: 0x7fff096df828 <-- how can the pointer to myotherints array be stored here when dereferencing it (*) returns 20 and...
&myotherints[0]: 0x2308010   <-- dereferencing this address with [] also returns 20, yet they are different memory locations unlike myints

&j: 0x7fff096df824 
*/

是不是说myint是一个"C风格数组",而myotherints是一个"C++风格数组"？

如果我理解正确,myotherints是一个指针但myints是一个数组,大多数时候表现得像一个指针？因此,虽然您可以使用myint进行指针处理,但有时候它不像指针那样,即使用&来显示其地址.这意味着myints与指针的类型不同.它的类型是"一系列的整数"吗？

存储myint(myins的东西,而不是其数组中的值),如果它总是自动解除引用数组存储的位置,我怎么能显示它的地址？与使用C++样式的新数组返回的指针不同？

这些在功能上以不同的方式表现在记忆中吗？

任何能够真正巩固我理解的文档提示或指示都将非常感激.谢谢!