失败的示例后,guard-rspec重新运行包含shared_examples而不是实际spec文件的文件

我有一个功能规格,如spec/features/awesome_feature_spec.rb需要spec/shared_examples/awesome_spec.rb.后者包含我正在使用的所有shared_examples awesome_feature_spec.rb.当一个示例失败并且我编辑一个文件来修复它并保存它时,guard会尝试再次运行该示例,但它会直接运行awesome_feature.rb而不是awesome_feature_spec.rb因为失败的共享示例所在awesome_feature.rb.这当然会导致错误,因为它需要运行awesome_feature_spec.rb,这是实际的功能规范.

这就是我的Guardfile的样子:

guard :rspec do
  watch(%r{^spec/.+_spec\.rb$})
  watch(%r{^lib/(.+)\.rb$})     { |m| "spec/lib/#{m[1]}_spec.rb" }
  watch('spec/spec_helper.rb')  { "spec" }

  # Rails example
  watch(%r{^app/(.+)\.rb$})                           { |m| "spec/#{m[1]}_spec.rb" }
  watch(%r{^app/(.*)(\.erb|\.haml|\.slim)$})          { |m| "spec/#{m[1]}#{m[2]}_spec.rb" }
  watch(%r{^app/controllers/(.+)_(controller)\.rb$})  { |m| ["spec/routing/#{m[1]}_routing_spec.rb", "spec/#{m[2]}s/#{m[1]}_#{m[2]}_spec.rb", "spec/acceptance/#{m[1]}_spec.rb"] }
  watch(%r{^spec/support/(.+)\.rb$})                  { "spec" }
  watch('config/routes.rb')                           { "spec/routing" }
  watch('app/controllers/application_controller.rb')  { "spec/controllers" }

  # Capybara features specs
  watch(%r{^app/views/(.+)/.*\.(erb|haml|slim)$})     { |m| "spec/features/#{m[1]}_spec.rb" }
  watch(%r{^spec/shared_examples.*/(.+)\.rb$})      { |m| "spec/features/#{m[1]}_spec.rb" }

  # Turnip features and steps
  watch(%r{^spec/acceptance/(.+)\.feature$})
  watch(%r{^spec/acceptance/steps/(.+)_steps\.rb$})   { |m| Dir[File.join("**/#{m[1]}.feature")][0] || 'spec/acceptance' }
end

任何人都可以帮助我保护运行功能规范而不是包含共享示例的文件吗？

非常感谢你提前:)