我有一个在Base64中编码的字符串:
eJx9xEERACAIBMBKJyKDcTzR_hEsgOxjAcBQFVVNvi3qEsrRnWXwbhHOmzWnctPHPVkPu-4vBQ==
如何用Scala语言解码它?
我试着用:
val bytes1 = new sun.misc.BASE64Decoder().decodeBuffer(compressed_code_string)
但是当我将字节数组与我在Python语言中生成的正确数组进行比较时,就会出现错误.这是我在python中使用的命令:
import base64 base64.urlsafe_b64decode(compressed_code_string)
Scala中的字节数组是:
(120, -100, 125, -60, 65, 17, 0, 32, 8, 4, -64, 74, 39, 34, -125, 113, 60, -47, -2, 17, 44, -128, -20, 99, 1, -64, 80, 21, 85, 77, -66, 45, -22, 18, -54, -47, -99, 101, -16, 110, 17, -50, -101, 53, -89, 114, -45, -57, 61, 89, 15, -69, -2, 47, 5)
而在python中生成的是:
(120, -100, 125, -60, 65, 17, 0, 32, 8, 4, -64, 74, 39, 34, -125, 113, 60, -47, -2, 17, 44, -128, -20, 99, 1, -64, 80, 21, 85, 77, -66, 45, -22, 18, -54, -47, -99, 101, -16, 110, 17, -50, -101, 53, -89, 114, -45, -57, 61, 89, 15, -69, -18, 47, 5)
请注意,数组末尾有一个区别