Matplotlib:如何使用broken_barh的时间戳？

据我所知,大熊猫根据索引的频率使用周期值绘制时间序列.这是有道理的,因为matplotlib只将数字理解为轴的值,因此您的调用broken_barh失败,因为您传递的是非数字值.

要获取您需要使用的时间戳周期的整数值.to_period().看到:

In [110]: pd.to_datetime('2014-04-02').to_period('D').ordinal
Out[110]: 16162

In [111]: pd.to_datetime('2014-04-02').to_period('W').ordinal
Out[111]: 2310

然后,根据您的时间戳间隔(天,周,月等),您需要确定要用于折断条的宽度.

在下面的示例中,频率为1天,一周的条宽为7个单位.

import numpy as np
import matplotlib.pylab as plt
import pandas as pd

idx = pd.date_range('2013-04-01', '2013-05-18', freq='D')
df = pd.DataFrame({'values': np.random.randn(len(idx))}, index=idx)
ax = df.plot()

start_period = idx[0].to_period('D').ordinal
bar1 = [(start_period, 7), (start_period + 10, 5), (start_period + 25, 4)]
bar2 = [(start_period, 1), (start_period + 22, 3), (start_period + 40, 2)]
ax.broken_barh(bar1, [2, .2], facecolor='red')
ax.broken_barh(bar2, [-2, .2], facecolor='green')
plt.show()