问

Gson:StackOverflowError

经典黑丝的诱惑发布于 2023-02-05 12:03

overflow

以下代码导致StackOverflowError.代码的目的是从java类创建一个json字符串.

for (ControlTransaction crt : ctrList) {
                crt= new ControlTransaction();// for test, Still issue
                final Gson gson = new GsonBuilder().registerTypeAdapter(
                ControlTransaction.class,
                  new ControlTransactionSerializer()).create();
                String jsonControlTransactionString = gson.toJson(crt);
                strList.add(jsonControlTransactionString);

            }

我的班级看起来像

public class ControlTransaction implements IsSerializable, Serializable ,IsBean{
    private long id;
    private String value; // H
    private String lastValue; // H
    private FormTransaction formTransaction;
    private List gridRows;
    private ControlTransaction referenceGridTransaction;
    private RowTransaction fkRowTransaction;
    private ReportTransaction reportTransaction;
    //getters ... setters
}

堆栈跟踪就像这样,让我知道

Caused by: java.lang.StackOverflowError
at com.google.gson.stream.JsonWriter.(JsonWriter.java:190)
at com.google.gson.internal.bind.JsonTreeWriter.(JsonTreeWriter.java:58)
at com.google.gson.Gson.toJsonTree(Gson.java:478)
at com.google.gson.Gson$3.serialize(Gson.java:140)
at com.nextenders.common.ControlTransactionSerializer.serialize(ControlTransactionJsonUtil.java:129)
at com.nextenders.common.ControlTransactionSerializer.serialize(ControlTransactionJsonUtil.java:1)
at com.google.gson.TreeTypeAdapter.write(TreeTypeAdapter.java:70)
at com.google.gson.Gson.toJson(Gson.java:586)
at com.google.gson.Gson.toJsonTree(Gson.java:479)
at com.google.gson.Gson$3.serialize(Gson.java:140)
at com.nextenders.common.ControlTransactionSerializer.serialize(ControlTransactionJsonUtil.java:129)
at com.nextenders.common.ControlTransactionSerializer.serialize(ControlTransactionJsonUtil.java:1)
at com.google.gson.TreeTypeAdapter.write(TreeTypeAdapter.java:70)
at com.google.gson.Gson.toJson(Gson.java:586)
at com.google.gson.Gson.toJsonTree(Gson.java:479)
at com.google.gson.Gson$3.serialize(Gson.java:140)
at com.nextenders.common.ControlTransactionSerializer.serialize(ControlTransactionJsonUtil.java:129)
at com.nextenders.common.ControlTransactionSerializer.serialize(ControlTransactionJsonUtil.java:1)
at com.google.gson.TreeTypeAdapter.write(TreeTypeAdapter.java:70)
at com.google.gson.Gson.toJson(Gson.java:586)
at com.google.gson.Gson.toJsonTree(Gson.java:479)
at com.google.gson.Gson$3.serialize(Gson.java:140)

这是我serializer和deserializer

class ControlTransactionDeserializer implements
        JsonDeserializer {
    @Override
    public ControlTransaction deserialize(JsonElement json, Type type,
            JsonDeserializationContext context) throws JsonParseException {
        return context.deserialize(json, type);
    }
}

class ControlTransactionSerializer implements
        JsonSerializer {

    @Override
    public JsonElement serialize(ControlTransaction ctr, Type type,
            JsonSerializationContext context) {
        return context.serialize(ctr, type);
    }
}

什么在后端发生.我刚刚传递了一个空对象,这意味着新的ControlTransaction(),仍然无法解析.

1 个回答

a的要点JsonSerializer是序列化Object的字段,而不是对象本身.但是,您传递的是已经告诉过的对象Gson序列化.下列
```
@Override
public JsonElement serialize(ControlTransaction ctr, Type type,
        JsonSerializationContext context) {
    return context.serialize(ctr, type);
}
```
相当于
```
@Override
public JsonElement serialize(ControlTransaction ctr, Type type,
        JsonSerializationContext context) {
    return new GsonBuilder().registerTypeAdapter(
            ControlTransaction.class,
              new ControlTransactionSerializer()).create().toJsonTree(ctr);
}
```
我希望你能看到的是进入递归循环.

在JsonSerializationContext基本的底层结构Gson对象使用序列化你的对象.当它看到您的类型时ControlTransaction,它将委托给您的自定义JsonSerializer.但是你的JsonSerializer意志会把它发回去,JsonSerializationContext循环继续.
2023-02-05 12:05 回答

mobiledu2502930075

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