好的,所以我先显示我的代码,然后我会解释我需要帮助的内容.
Random isServerChance = new Random(); Random isGood = new Random(); Random isBad = new Random(); // Some IDs which are considered "Good" int isGoodTable[] = { 1038, 1040, 1042, 1044 }; // Some IDs which are considered "Bad" int isBadTable[] = { 6570, 6585, 952, 969 }; // Based on this roll, will pick which cat is used. Good, or Bad. int isServerRoll = isServerChance.nextInt(6); // If it's > 3 it's going to be a "Good" item, if it's not, it's a bad // item. if (isServerRoll > 3) { int isGoodValue = isGood.nextInt(isGoodTable.length); System.out.println("You've received a rare item! You got a: " + isGoodTable[isGoodValue]); } else { int isBadValue = isBad.nextInt(isBadTable.length); System.out.println("You've received a normal item. You've got a: " + isBadTable[isBadValue]); }
}
好的,所以这将打印:你收到了一个正常的项目.你有一个:969 || 你收到了一件稀有物品!你有一个:1042.
假设969的int值是一个Spade.我可以从上面的一个int表中使969等于一个字符串数组吗?
所以,如果我登陆969,它会说:"你收到了正常的物品.你有一个:锹!"
我有点新,所以我不确定这是否可行,但我不想为每个ID加载if语句.
谢谢
看来你只需要字符串数组而不是整数数组:
String[] isBadTable = { "Foo", "Bar", "Baz", "Spade" };
阅读有关数组的教程.